sqlite_num_rows
SQLiteResult::numRows
(PHP 5 < 5.4.0, PECL sqlite >= 1.0.0)
sqlite_num_rows -- SQLiteResult::numRows — Returns the number of rows in a buffered result set
说明
$result
)面向对象风格 (method):
Returns the number of rows in the buffered result
set.
参数
-
result -
The SQLite result resource. This parameter is not required when using the object-oriented method.
Note:
此函数不能用于未缓冲的结果句柄。
返回值
Returns the number of rows, as an integer.
范例
Example #1 Procedural example
<?php
$db = sqlite_open ( 'mysqlitedb' );
$result = sqlite_query ( $db , "SELECT * FROM mytable WHERE name='John Doe'" );
$rows = sqlite_num_rows ( $result );
echo "Number of rows: $rows " ;
?>
Example #2 Object-oriented example
<?php
$db = new SQLiteDatabase ( 'mysqlitedb' );
$result = $db -> query ( "SELECT * FROM mytable WHERE name='John Doe'" );
$rows = $result -> numRows ();
echo "Number of rows: $rows " ;
?> 参见
- sqlite_changes() - Returns the number of rows that were changed by the most recent SQL statement
- sqlite_query() - Executes a query against a given database and returns a result handle
- sqlite_num_fields() - Returns the number of fields in a result set
用户评论:
[#1] be {a} t {dawt} pl [2015-10-19 08:43:12]
@rezaamya
$db = new SQLite3('databasename.db');
$result = $db->query("SELECT * FROM users");
$rows = count ($result);
echo "Number of rows: $rows";
$rows value should always be 1
... even if the query is invalid
I tested that on
SQLite Library 3.7.7.1
[#2] rezaamya at gmail dot com [2014-06-17 15:11:09]
neither of "sqlite_num_rows($result)" and "$result->numRows()" is not working on SQLite3 !
you should use this way:
$db = new SQLite3('databasename.db');
$result = $db->query("SELECT * FROM users");
$rows = count ($result);
echo "Number of rows: $rows";