SplFileObject::__construct
(PHP 5 >= 5.1.0)
SplFileObject::__construct — Construct a new file object.
说明
$filename
[, string $open_mode = "r"
[, bool $use_include_path = false
[, resource $context
]]] )Construct a new file object.
参数
-
filename -
The file to read.
Tip如已启用fopen 包装器，在此函数中， URL 可作为文件名。关于如何指定文件名详见 fopen() 。各种 wapper 的不同功能请参见 支持的协议和封装协议，注意其用法及其可提供的预定义变量。
-
open_mode -
The mode in which to open the file. See fopen() for a list of allowed modes.
-
use_include_path -
Whether to search in the include_path for
filename. -
context -
A valid context resource created with stream_context_create() .
返回值
没有返回值。
错误／异常
Throws a RuntimeException if the filename cannot be opened.
范例
Example #1 SplFileObject::__construct() example
This example opens the current file and iterates over its contents line by line.
<?php
$file = new SplFileObject ( __FILE__ );
foreach ( $file as $line_num => $line ) {
echo "Line $line_num is $line " ;
}
?> 以上例程的输出类似于：
Line 0 is <?php
Line 1 is $file = new SplFileObject(__FILE__);
Line 2 is foreach ($file as $line_num => $line) {
Line 3 is echo "Line $line_num is $line";
Line 4 is }
Line 5 is ?>
参见
- SplFileInfo::openFile() - Gets an SplFileObject object for the file
- fopen() - 打开文件或者 URL
用户评论:
[#1] majna [2014-08-20 22:09:23]
(PHP >= 5.3) If filename is a directory, a LogicException will be thrown: "Cannot use SplFileObject with directories"